N찍기 문제

5 입력 ==> 1, 2, 3, 4, 5  를 출력하시오.

 

const readline = require('readline');

const rl = readline.createInterface({
  input: process.stdin,
  output: process.stdout
});
rl.on('line', (a) => {
  const input=parseInt(a)
  for(i=1; i<=input; i++){
    let answer=input-(input-i)
    console.log(answer)
  }
  rl.close();
});

my code : 5-4, 5-3, 5-2, 5-1, 5-5를 출력함

 

const fs = Number(require('fs').readFileSync('/dev/stdin').toString()); 
let result = ''; 
for(let i = 1 ; i<=fs ; i++){
	result += i.toString() +'\n'; 
}
 
console.log(result);

short code : 입력변수 숫자와 관계없이, i를 1부터 input개까지 출력